Two Forms for Greens Theorem

 

The notation  for integration around a closed curve. We elaborate further on the notation here.      

A simple closed curve C can be traversed in two possible directions. (Recall that a curve is simple if it does not cross itself.) The curve is traversed counterclockwise, and said to be positively oriented, if the region it encloses is always to the left of an object as it moves along the path. Otherwise it is traversed clockwise and negatively oriented. The line integral of a vector field F along C reverses sign if we change the orientation. We use the notation 

for the line integral when the simple closed curve C  is traversed counterclockwise, with its positive orientation. 

In one form, Greens Theorem says that the counterclockwise circulation of a vector field around a simple closed curve is the double integral of the k-component of the curl of the field over the region enclosed by the curve. 

 

 

THEOREM Greens Theorem (Circulation-Curl or Tangential Form) Let C

be a piecewise smooth, simple closed curve enclosing a region in the plane. Let  be a vector field with M and N having continuous first partial derivatives in an open region containing RThen the counterclockwise circulation of around equals the double integral of  over R.

A second form of Green’s Theorem says that the outward flux of a vector field across a simple closed curve in the plane equals the double integral of the divergence of the field over the region enclosed by the curve.

 

 

THEOREM 2 Green’s Theorem (Flux-Divergence or Normal Form) Let C

be a piecewise smooth, simple closed curve enclosing a region in the plane. Let  be a vector field with and having continuous first partial derivatives in an open region containing RThen the outward flux of  F across C equals the double integral of div F  over the region R enclosed by C.

The two forms of Green’s Theorem are equivalent.

 

EXAMPLE 3: Verify both forms of Green’s Theorem for the vector field

and the region R bounded by the unit circle

 

 

Evaluating   and computing the partial derivatives of the components of F

, we have
 
The two sides of Equation (3) are
 

The two sides of Equation (4) are